2x^2-18x+80=40

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Solution for 2x^2-18x+80=40 equation:


Simplifying
2x2 + -18x + 80 = 40

Reorder the terms:
80 + -18x + 2x2 = 40

Solving
80 + -18x + 2x2 = 40

Solving for variable 'x'.

Reorder the terms:
80 + -40 + -18x + 2x2 = 40 + -40

Combine like terms: 80 + -40 = 40
40 + -18x + 2x2 = 40 + -40

Combine like terms: 40 + -40 = 0
40 + -18x + 2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(20 + -9x + x2) = 0

Factor a trinomial.
2((4 + -1x)(5 + -1x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(4 + -1x)' equal to zero and attempt to solve: Simplifying 4 + -1x = 0 Solving 4 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1x = 0 + -4 -1x = 0 + -4 Combine like terms: 0 + -4 = -4 -1x = -4 Divide each side by '-1'. x = 4 Simplifying x = 4

Subproblem 2

Set the factor '(5 + -1x)' equal to zero and attempt to solve: Simplifying 5 + -1x = 0 Solving 5 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1x = 0 + -5 -1x = 0 + -5 Combine like terms: 0 + -5 = -5 -1x = -5 Divide each side by '-1'. x = 5 Simplifying x = 5

Solution

x = {4, 5}

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